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Elazığ
Kayseri
Şırnak
Antep
FHİLHY<a href="https://bayanlarsitesi.com/adana-escort/" rel="nofollow">Adana</a><br /><a href="https://bayanlarsitesi.com/elazig-escort/" rel="nofollow">Elazığ</a><br /><a href="https://bayanlarsitesi.com/kayseri-escort/" rel="nofollow">Kayseri</a><br /><a href="https://bayanlarsitesi.com/sirnak-escort/" rel="nofollow">Şırnak</a><br /><a href="https://bayanlarsitesi.com/antep-escort/" rel="nofollow">Antep</a><br />FHİLHYDataByteChaser666noreply@blogger.comtag:blogger.com,1999:blog-1570852996024207044.post-47818210153251665712023-01-28T00:46:40.105-08:002023-01-28T00:46:40.105-08:00Great post. Your post is very beneficial for me. T...Great post. Your post is very beneficial for me. Thank you for consistently providing fascinating and valuable information about integrate 1/(sinx + cosx) dx to your readers; your blog is doing very well. Meanwhile, you can look at the <a href="https://bestassignmentwriting.co.uk/coursework/business-coursework-help/" rel="nofollow">business coursework help</a> which was extremely useful to me and other readers.royalbert867https://www.blogger.com/profile/04471351333309533717noreply@blogger.comtag:blogger.com,1999:blog-1570852996024207044.post-6127896624742856772016-03-12T11:29:03.845-08:002016-03-12T11:29:03.845-08:00Use - (a^3 + b^3) identity...it goes the same wayUse - (a^3 + b^3) identity...it goes the same wayAnonymoushttps://www.blogger.com/profile/09203858901663861405noreply@blogger.comtag:blogger.com,1999:blog-1570852996024207044.post-79697730249927418722015-03-29T08:04:32.151-07:002015-03-29T08:04:32.151-07:00plz solve integration of 1/((sinx)^3+(cosx)^3)plz solve integration of 1/((sinx)^3+(cosx)^3)Anonymoushttps://www.blogger.com/profile/18060348666476797018noreply@blogger.comtag:blogger.com,1999:blog-1570852996024207044.post-38186343324500267322014-09-25T23:58:57.302-07:002014-09-25T23:58:57.302-07:00sin x + cos x = sqrt 2 sin ( x + 45)
Hence Integ ...sin x + cos x = sqrt 2 sin ( x + 45)<br /><br />Hence Integ 1/(sin x +cos x)dx <br />= sqrt(2) * Integral cosec(x+45)<br /><br />= sqrt(2)*ln|csc(x+pie/4)+cot(x+pie/4)| + C<br />=sqrt(2)log (tanx/2+pie/8)+cAnonymoushttps://www.blogger.com/profile/07818496084352257020noreply@blogger.comtag:blogger.com,1999:blog-1570852996024207044.post-37522375820800497092014-08-17T07:18:18.113-07:002014-08-17T07:18:18.113-07:00How do we integrate 1/((sinx)^5+(cosx)^5)How do we integrate 1/((sinx)^5+(cosx)^5)Anonymoushttps://www.blogger.com/profile/12934464722300617428noreply@blogger.comtag:blogger.com,1999:blog-1570852996024207044.post-38112864903001319482014-05-15T23:07:08.481-07:002014-05-15T23:07:08.481-07:00instead of doing this there 's another short m...instead of doing this there 's another short method <br /> 1 / (sin x + cos x) ? Then <br />sin x + cos x = sqrt 2 sin ( x + 45) <br /><br />Hence Integ 1 / (sin x +cos x) dx = sqrt 2 Integral cosec (x + 45) <br /><br />= - sqrt 2 ln I csc ( x+ 45) + cot (x + 45) I + C Anonymoushttps://www.blogger.com/profile/09070941367183134092noreply@blogger.comtag:blogger.com,1999:blog-1570852996024207044.post-57800498905307010322014-03-20T12:44:32.663-07:002014-03-20T12:44:32.663-07:00talent
talent<br />Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-1570852996024207044.post-19205872616266634362013-02-17T23:29:38.059-08:002013-02-17T23:29:38.059-08:00Instead Of Partial Fractions , You Could Have Had ...Instead Of Partial Fractions , You Could Have Had Used These Formula<br />∫dx/(x^2 - a^2) = (1/2a)(log (x-a)/(x+a)) + c <br />Would Have Had Become Way Simpler !Anonymoushttps://www.blogger.com/profile/03297725322125401212noreply@blogger.comtag:blogger.com,1999:blog-1570852996024207044.post-56487667264865592742011-10-01T09:11:14.439-07:002011-10-01T09:11:14.439-07:00sin x + cos x = sqrt 2 sin ( x + 45)
Hence Integ ...sin x + cos x = sqrt 2 sin ( x + 45)<br /><br />Hence Integ 1/(sin x +cos x)dx <br />= sqrt(2) * Integral cosec(x+45)<br /><br />= -sqrt(2)*ln|csc(x+45)+cot(x+45)| + CTutorState.comhttp://www.tutorstate.com/noreply@blogger.comtag:blogger.com,1999:blog-1570852996024207044.post-75649382120213366182011-10-01T08:25:11.815-07:002011-10-01T08:25:11.815-07:00http://tutorstate.blogspot.com/2011/10/do-integral...http://tutorstate.blogspot.com/2011/10/do-integral-of-1sinxcosx-with-respect.html#linksTutorState.comhttp://www.tutorstate.com/noreply@blogger.comtag:blogger.com,1999:blog-1570852996024207044.post-51971418724390050492011-10-01T07:44:14.899-07:002011-10-01T07:44:14.899-07:00Function 1/(cos(x)+sin(x))
∫fdx =(log(sin(x)+(sqrt...Function 1/(cos(x)+sin(x))<br />∫fdx =(log(sin(x)+(sqrt(2)-1)*cos(x)+ sqrt(2)-1)-log(sin(x)+(-sqrt(2)-1)*cos(x) -sqrt(2)-1))/sqrt(2)Unknownhttps://www.blogger.com/profile/14038348003627791116noreply@blogger.comtag:blogger.com,1999:blog-1570852996024207044.post-86977716230899209202011-10-01T07:42:26.774-07:002011-10-01T07:42:26.774-07:00See more: http://www.numberempire.com/integralcalc...See more: http://www.numberempire.com/integralcalculator.php?function=1%2F%28cos%28x%29%2Bsin%28x%29%29&var=x&answers=Unknownhttps://www.blogger.com/profile/14038348003627791116noreply@blogger.comtag:blogger.com,1999:blog-1570852996024207044.post-80576325394269551232011-10-01T07:22:41.344-07:002011-10-01T07:22:41.344-07:00I have found out an another result form in the Wol...I have found out an another result form in the Wolfram Mathematica Online Integrator. See: http://www.facebook.com/photo.php?fbid=226946374025071&set=a.226946367358405.75292.217757241610651&type=1&theater<br /><br />Wolfram Mathematica Online Integrator: http://integrals.wolfram.com/index.jspUnknownhttps://www.blogger.com/profile/14038348003627791116noreply@blogger.comtag:blogger.com,1999:blog-1570852996024207044.post-14046615433252672302011-10-01T04:45:57.995-07:002011-10-01T04:45:57.995-07:00Its a tough question.. cant be solved if u dont kn...Its a tough question.. cant be solved if u dont know the hint to multiply (cosx-sinx) in numerator and denominatorAnonymousnoreply@blogger.com